vault backup: 2025-03-19 22:01:46

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Marco Realacci 2025-03-19 22:01:46 +01:00
parent 40e8408656
commit 03c186157e

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@ -24,6 +24,7 @@ Since DLF is deadlock free, it is sufficient to prove that at least one process
If TURN = k and $p_k$ invoked lock, then it finds TURN = k and exits its wait.
Otherwise, any other process will find `FLAG[TURN] = down` and exits from its wait.
###### Is it bounded bypass?
**Lemma 1:** if TURN = i and `FLAG[i] = up` then $p_i$ enters the CS in at most n-1 iterations
Observation 1: TURN changes only when FLAG[i] is down (after pi has completed its CS)