vault backup: 2025-03-18 16:45:04
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@ -66,9 +66,11 @@ We now show that $\to$ is acyclic.
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This said, we can say that **every DAG admits a topological order** (a total order of its nodes that respects the edges), we will call $\to'$ the topological order for $\to$
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Let us define a linearization of $\hat{H}$ as follows: $$\hat{S}=inv(op1)res(op1)$$
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Let us define a linearization of $\hat{H}$ as follows: $$\hat{S}=inv(op1)res(op1)inv(op2)res(op2)...$$
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we would have the topological order: $op1\to'op2\to'...$
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$\hat{S}$ is clearly sequential. Moreover:
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1. $\forall X :\hat{S}|_{X} = \hat{S}_X (\in semantics(X))$. Indeed:
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> [!PDF|red] class 6, p.6> we would have a cycle of length
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>
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> we would contraddict op2 ->x op3
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