diff --git a/Concurrent Systems/notes/14 Checking bisimilarity, an inference system.md b/Concurrent Systems/notes/14 Checking bisimilarity, an inference system.md
index 1671b8d..95f71e1 100644
--- a/Concurrent Systems/notes/14 Checking bisimilarity, an inference system.md	
+++ b/Concurrent Systems/notes/14 Checking bisimilarity, an inference system.md	
@@ -52,10 +52,10 @@ $P$ is in standard form if and only if $P \triangleq \sum_{i}\alpha_{i}P_{i}$ an
 2. $P \triangleq \sum_{i \in I}\alpha_{i}P_{i}$. By induction $\forall P_{i} \exists P_{i}'$ in a standard form s.t. $\vdash P_{1}=P_{1}'$
 	Let's now consider a context: $\alpha_{1}.☐ + \sum_{i \in I}\alpha_{i}P_{i}$
 	Now we fill the context with $P_1$ and remove 1 from the set I (basically we pull it out from the summation): $$\alpha_{1}.P_{1} + \sum_{i \in I\setminus \{ 1 \}}\alpha_{i}P_{i}$$
-	Now we replace $P_1$ with $P_{1}'$
-![](images/Pasted%20image%2020250429084921.png)
-![](images/Pasted%20image%2020250429084950.png)
-replacing one by one every continuation with its standard form, obtaining standard form.
+	Now we replace $P_1$ with $P_{1}'$ and obtain: $$=\alpha_{1}.P_{1}' + \sum_{i \in I\setminus \{ 1 \}}\alpha_{i}P_{i}$$
+	imagine doing this until you pulled everything out... Standard form!
+	
+3. 
 
 ![](images/Pasted%20image%2020250429085319.png)