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Concurrent Systems/notes/12b - CCS cose varie.md

@@ -39,6 +39,7 @@ NO: the problem is that, for example:
 So we can try with $$S = \{ (α.P+α.P+M , α.P+M) \} ∪ \{(P,P)\}$$
 But it is not yet a bisimulation.
 P –β–> P’ (challenge and reply), but we don't have (P', P') in S.
+(Questo per garantire che funzioni in qualsiasi caso, con qualsiasi P che eventualmente evolve in P')
 
 So let's try with: $$S = \{ (α.P+α.P+M , α.P+M) \} ∪ Id$$
 Let's go!