vault backup: 2025-03-08 17:46:57

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Marco Realacci 2025-03-08 17:46:57 +01:00
parent 8efa7b29fa
commit 561e4939e7
2 changed files with 8 additions and 11 deletions

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@ -196,6 +196,7 @@
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@ -92,20 +92,17 @@ Every solution to a problem should satisfy at least:
>[!warning] So safety is necessary for correctness, liveness for meaningfulness.
##### In the context of MUTEX:
- **Safety:** there is at most one process at a time in a CS.
- **Safety:** there is at most one process at a time in a CS (*mutual exclusion*).
- **Liveness:**
- **Deadlock freedom:** if there is at least one invocation of lock, eventually after at least one process enters a C.S.
- **Starvation freedom:** every invocation of lock eventually grants access to the associated C.S.
- **Bounded bypass:** let $n$ be the number of processes; then, there exists $f: N \to N$ s.t. every lock enters the C.S. after at most $f(n)$ other C.S.s (The process must win in at most f(n) steps).
- **Deadlock freedom:** if there is at least one invocation of `lock`, one process will eventually enter the critical section. This means that **the system is not blocked forever**.
- **Starvation freedom:** every invocation of lock eventually grants access to the associated CS (a process won't be stuck forever while other processes are racing for the CS).
- **Bounded bypass:** like starvation freedom, but stronger! We define an upper bound on the number of failures. Let $n$ be the number of processes; then, there exists $f: N \to N$ s.t. every lock enters the C.S. after at most $f(n)$ other CSs (The process must enter the CS in at most $f(n)$ steps).
todo: riscrivere meglio l'ultimo
Both inclusions are strict:
Deadlock freedom $\not{\implies}$ Starvation freedom
**Both inclusions are strict:**
$$\text{Deadlock freedom} \not \implies \text{Starvation freedom}$$
![[Pasted image 20250303093116.png]]
Starvation freedom $not \implies$ Bounded bypass
Starvation freedom $\not \implies$ Bounded bypass
Assume a $f$ and consider the scheduling above, where p2 wins $f(3)$ times and so does p3, then p1 looses (at least) $2f(3)$ times before winning.
### Atomic R/W registers