vault backup: 2025-03-03 10:46:24
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@ -218,3 +218,5 @@ Induction (true for ℓ, to be proved for ℓ+1):
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- let $p_x$ be the last one that writes `A_Y[ℓ+1]`, so `A_Y[ℓ+1]=x`
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- for $p_x$ to pass at level ℓ+1, it must be that $∀k≠x. F[k] < ℓ+1$, then $p_x$ is the only proc at level ℓ+1 and the thesis holds, since 1<=n-ℓ-1
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- otherwise, $p_x$ is blocked in the wait and so we have at most n-ℓ-1 processes at level ℓ+1 (i.e., those at level ℓ, that by induction are at most n-ℓ, except for px that is blocked in its (ℓ+1)-th wait).
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##### Starvation freedom proof
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