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Marco Realacci 2025-05-05 09:17:04 +02:00
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.obsidian/workspace.json vendored
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@ -213,9 +213,9 @@
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Concurrent Systems/notes/15 - A formal language for LTSs.md
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@ -45,3 +45,7 @@ To simplify the proof, let us modify the set of formulae by allowing conjunction
*Inductive step:* Let's assume the thesis for every tree of height at most h. Let h+1 be the height of $\phi$. Let's distinguish on the outmost operator in $\phi$ *Inductive step:* Let's assume the thesis for every tree of height at most h. Let h+1 be the height of $\phi$. Let's distinguish on the outmost operator in $\phi$
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(<=) We prove that $$R \triangleq \{ (P, Q) : L(P)=L(Q) \}$$ is a simulation; this suffices, since the relation just defined is trivially symmetric (so is a bisimulation too).
Let $(P, Q) \in R$ and $$