vault backup: 2025-04-14 08:49:56

.obsidian/workspace.json

@@ -242,6 +242,7 @@
   "lastOpenFiles": [
     "Concurrent Systems/slides/class 11.pdf",
     "Concurrent Systems/notes/11 - LTSs and Bisimulation.md",
+    "Pasted image 20250414084615.png",
     "Pasted image 20250414082824.png",
     "Concurrent Systems/notes/12.md",
     "Concurrent Systems/slides/class 12.pdf",
@@ -284,7 +285,6 @@
     "Foundation of data science/class 9.pdf",
     "Concurrent Systems/slides/class 10.pdf",
     "Concurrent Systems/ignore this folder",
-    "Concurrent Systems/notes/images/Pasted image 20250401083747.png",
     "Senza nome.canvas"
   ]
 }

Concurrent Systems/notes/11 - LTSs and Bisimulation.md

@@ -61,3 +61,9 @@ If S contained one among (p1,q1) or (p1,q2), then it would not be a simulation:
 p0 is simulated by q0: $$S = {(p0, q0), (p1, q2), (p2, q3)}$$
 q0 is simulated by p0: $$S′ ={(q0,p0),(q1,p1),(q2,p1),(q3,p2)}$$
 However, p0 and q0 are not bisimilar: the transition q0 -> a -> q1 is not bisimulable by any transition from p0 (ndeed, p0 –a–> p1 does not suffice, because p1 can perform a b and so cannot be bisimilar to q1).
+
+#### Bisimulation is NOT isomorfism
+![](../../Pasted%20image%2020250414084615.png)
+
+$S = \{(p0,q0), (p1,q1), (p2,q1), (p0,q2)\}$
+$S^{−1} = \{(q0,p0), (q1,p1), (q1,p2), (q2,p0)\}$