vault backup: 2025-04-15 08:55:18
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@ -37,7 +37,7 @@ NO: the problem is that, for example:
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- BUT (P,P) in general does NOT belong to S!
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So we can try with $$S = \{ (α.P+α.P+M , α.P+M) \} ∪ \{(P,P)\}$$
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But it is not yet a bisimulation.
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But it is not yet a bisimulation.
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P –β–> P’ (challenge and reply), but we don't have (P', P') in S.
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So let's try with: $$S = \{ (α.P+α.P+M , α.P+M) \} ∪ Id$$
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