vault backup: 2025-04-30 19:48:22
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@ -54,14 +54,15 @@ $P$ is in standard form if and only if $P \triangleq \sum_{i}\alpha_{i}P_{i}$ an
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Now we fill the hole (*er bucio*) with $P_1$ and remove 1 from the set I (basically we pull it out from the summation): $$\alpha_{1}.P_{1} + \sum_{i \in I\setminus \{ 1 \}}\alpha_{i}P_{i}$$
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Now we fill the hole (*er bucio*) with $P_1$ and remove 1 from the set I (basically we pull it out from the summation): $$\alpha_{1}.P_{1} + \sum_{i \in I\setminus \{ 1 \}}\alpha_{i}P_{i}$$
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Now we replace $P_1$ with $P_{1}'$ and obtain: $$=\alpha_{1}.P_{1}' + \sum_{i \in I\setminus \{ 1 \}}\alpha_{i}P_{i}$$
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Now we replace $P_1$ with $P_{1}'$ and obtain: $$=\alpha_{1}.P_{1}' + \sum_{i \in I\setminus \{ 1 \}}\alpha_{i}P_{i}$$
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imagine doing this until you pulled everything out... Standard form!
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imagine doing this until you pulled everything out... Standard form!
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3.
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### Axioms & Rules for Weak Bisimilarity
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### Axioms & Rules for Weak Bisimilarity
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#### Completeness theorem: $P \sim Q \implies \vdash P=Q$
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#### Example
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#### Example
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A server for exchanging messages, in its minimal version, receives a request for sending messages and delivers the confirmation of the reception
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A server for exchanging messages, in its minimal version, receives a request for sending messages and delivers the confirmation of the reception
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