vault backup: 2025-04-14 17:10:00

This commit is contained in:
Marco Realacci 2025-04-14 17:10:00 +02:00
parent 7227bcbc96
commit a8929fe551
2 changed files with 6 additions and 11 deletions

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@ -238,10 +238,10 @@
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@ -130,18 +130,13 @@ $$A' \mid B \xrightarrow{\tau} A \mid B'$$
##### ▶️ Step 3: Transition from B'
From the definition:
- $BB' \triangleq \bar{c}.B$
- So: B→cˉBB' \xrightarrow{\bar{c}} B
- $B' \triangleq \bar{c}.B$
- So: $B' \xrightarrow{\bar{c}} B$
Now use the **right parallel rule**:
B→cˉBAB→cˉAB\frac{B' \xrightarrow{\bar{c}} B}{A \mid B' \xrightarrow{\bar{c}} A \mid B}
$$\frac{B' \xrightarrow{\bar{c}} B}{A \mid B' \xrightarrow{\bar{c}} A \mid B}$$
✅ **Third transition:**
AB→cˉABA \mid B' \xrightarrow{\bar{c}} A \mid B
---
$$A \mid B' \xrightarrow{\bar{c}} A \mid B$$
## 🔄 Full Transition Path