diff --git a/.obsidian/workspace.json b/.obsidian/workspace.json
index e048ff4..60dd8cf 100644
--- a/.obsidian/workspace.json
+++ b/.obsidian/workspace.json
@@ -213,9 +213,10 @@
   },
   "active": "cdcc59f1bf6d4ae1",
   "lastOpenFiles": [
-    "Pasted image 20250505094841.png",
+    "Pasted image 20250505095249.png",
     "Concurrent Systems/slides/class 15.pdf",
     "Concurrent Systems/notes/15 - A formal language for LTSs.md",
+    "Pasted image 20250505094841.png",
     "Pasted image 20250505090959.png",
     "Pasted image 20250505090603.png",
     "Pasted image 20250505085454.png",
@@ -234,7 +235,6 @@
     "Concurrent Systems/notes/13 - Weak Bisimilarity.md",
     "Pasted image 20250430192526.png",
     "Pasted image 20250430183304.png",
-    "Pasted image 20250430175412.png",
     "Concurrent Systems/slides/class 13.pdf",
     "Concurrent Systems/slides/class 14.pdf",
     "Concurrent Systems/slides/class 12.pdf",
diff --git a/Concurrent Systems/notes/15 - A formal language for LTSs.md b/Concurrent Systems/notes/15 - A formal language for LTSs.md
index 05cae20..e9a639e 100644
--- a/Concurrent Systems/notes/15 - A formal language for LTSs.md	
+++ b/Concurrent Systems/notes/15 - A formal language for LTSs.md	
@@ -71,3 +71,20 @@ It is not very effective for concretely proving equivalences:
 	- so L(P2) is infinite because so is the action set
 
 #### Sub-Logics
+Let's consider the sub-logic without negation: $$\phi := TT | \phi \land \phi|◇ a \phi \quad where a \in Action$$
+*Remark:* the formula ☐aFF is not expressible anymore.
+Hence, we can only express through formulae what a process is able to do.
+
+Let's call L(P) the set of negation-free formulae satisfied by process P.
+
+##### Theorem
+P simulates Q if and only if $L(Q) \subseteq L(P)$
+
+*Proof:* The proof is similar to the one for the previous Theorem. The main difference is in the (⇐) implication, when φ = ⋄aφ′, because here we do not prove that the inclusion cannot be proper (indeed, in general it is not).
+
+An easy corollary of this result is that there is a double simulation between P and Q if and only if L¬(P) = L¬(Q).
+
+*Example:* it can be checked that L(P2) = L(P1)
+indeed, P1 can simulate P2 and viceversa, but the simulations are not bisimulations.
+![300](../../Pasted%20image%2020250505095249.png)
+
diff --git a/Pasted image 20250505095249.png b/Pasted image 20250505095249.png
new file mode 100644
index 0000000..9fdbed0
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