vault backup: 2025-03-18 09:29:12
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@ -30,4 +30,8 @@ $\hat{H}$ is linearizable if $\hat{H}|_{X}$ is linearizable, for all X in H
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(it is good to linearize complex traces)
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(it is good to linearize complex traces)
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For all X, let $\hat{S}_{X}$ be a linearization of $\hat{H}_{X}$
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For all X, let $\hat{S}_{X}$ be a linearization of $\hat{H}_{X}$
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- $\hat{S}_{X} def$
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- $\hat{S}_{X}$ defines a total order on the operations on X (call it $\to_{X}$)
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Let $\to$ denote $\to_{H} \cup \bigcup_{X \in H} \to _{X}$
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