vault backup: 2025-04-15 08:50:18

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Marco Realacci 2025-04-15 08:50:18 +02:00
parent 8c61a7d84f
commit d216fbf5aa

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@ -29,3 +29,16 @@ Which challenges can (a.P)\a have?
## Idempotency of Sum ## Idempotency of Sum
**Proposition:** $α.P+α.P+M α.P+M$ **Proposition:** $α.P+α.P+M α.P+M$
*Proof:* *Proof:*
$$S = \{ (α.P+α.P+M , α.P+M) \}$$
Is it a bisimulation?
NO: the problem is that, for example:
- α.P+α.P+M α> P
- α.P+M α> P
- BUT (P,P) in general does NOT belong to S!
So we can try with $$S = \{ (α.P+α.P+M , α.P+M) \} \{(P,P)\}$$
But it is not yet a bisimulation.
P –β–> P (challenge and reply), but we don't have (P', P') in S.
So let's try with: $$S = \{ (α.P+α.P+M , α.P+M) \} Id$$
Let's go!