vault backup: 2025-03-18 17:10:04
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@ -72,7 +72,11 @@ we would have the topological order: $op1\to'op2\to'...$
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$\hat{S}$ is clearly sequential. Moreover:
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$\hat{S}$ is clearly sequential. Moreover:
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1. $\forall X :\hat{S}|_{X} = \hat{S}_X (\in semantics(X))$, indeed:
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1. $\forall X :\hat{S}|_{X} = \hat{S}_X (\in semantics(X))$, indeed:
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- $<_{\hat{S}_X}=\to_X \subseteq \to'_X = \to_{\hat{S}|X}=<_{\hat{S}|X}$
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- $<_{\hat{S}_X}=\to_X \subseteq \to'_X = \to_{\hat{S}|X}=<_{\hat{S}|X}$
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- commenti
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- commento per non diventare scemi:
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- $\hat{S}_X$ lo storico ottenuto linearizzando $\hat{H}|_X$
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- $\hat{S}|_X$ lo storico che ottengo filtrando per le operazioni su X, partendo da $\hat{S}$, che a sua volta viene ottenuto linearizzando $\hat{H}$
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- $\to_X$
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- $\to|_X$
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> [!PDF|red] class 6, p.6> we would have a cycle of length
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> [!PDF|red] class 6, p.6> we would have a cycle of length
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>
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>
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> we would contraddict op2 ->x op3
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> we would contraddict op2 ->x op3
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