vault backup: 2025-04-08 10:51:20

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Marco Realacci 2025-04-08 10:51:20 +02:00
parent 8b8414f6ef
commit f0332f2b7b

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@ -53,4 +53,5 @@ Two states q and p are bisimulation equivalent (or, simply, bisimilar) if there
![](../../Pasted%20image%2020250408094749.png)
q0 is simulated by p0; this is shown by the following simulation relation: $$S = \{(q0,p0), (q1,p1), (q2,p1), (q3,p2), (q4,p3)\}$$
To let p0 be simulated by q0, we should have that p1 is simulated by q1 or q2.
If S contained one among (p1,q1) or (p1,q2), then it would not be a simulation: indeed, p1 can perform both a c (whereas q1 cannot) and a b (whereas q2 cannot)
If S contained one among (p1,q1) or (p1,q2), then it would not be a simulation: indeed, p1 can perform both a c (whereas q1 cannot) and a b (whereas q2 cannot).