vault backup: 2025-03-10 22:53:12
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@ -92,6 +92,7 @@ lock(i) :=
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```
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```
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- $p_n$ invokes lock alone, completes its CS and its new DATE is n
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- $p_n$ invokes lock alone, completes its CS and its new DATE is n
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- all other $p_i, i \in P$ (with P being the s)
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**Lemma 1:** Suppose we have $n$ processes, then $\not \exists p_{j} : DATE[j]=DATE[i] \forall i \in [0, n]$ (non esistono due processi con lo stesso valore per DATE)
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**Lemma 1:** Suppose we have $n$ processes, then $\not \exists p_{j} : DATE[j]=DATE[i] \forall i \in [0, n]$ (non esistono due processi con lo stesso valore per DATE)
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*Proof:*
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*Proof:*
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@ -104,4 +105,3 @@ lock(i) :=
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*Proof:*
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*Proof:*
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For the upper bound, it's trivial: DATE is either decreased or set to $n$.
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For the upper bound, it's trivial: DATE is either decreased or set to $n$.
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...
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...
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